\(\frac{31}{8}\)
\(\frac{17}{6}\)
\(\frac{19}{6}\)
\(\frac{27}{8}\)
A = {(x, y) : x2 ≤ y ≤ min {x + 2, 4 – 3x}
So, the area of the required region
A=\(\int_{-1}^{\frac{1}{2}}\)(x+2−x2)dx+\(\int_{1}^{\frac{1}{2}}\)(4−3x−x2)dx
=[\(\frac{x^2}{2}+2x-\frac{x^3}{3}\)]\(^{\frac{1}{2}}\)-1+[4x−\(\frac{3x^2}{2}\)−\(\frac{x^3}{3}\)]\(^{\frac{1}{2}}\)1
=(\(\frac{1}{8}\)+1−\(\frac{1}{24}\))−(\(\frac{1}{2}\)−2+\(\frac{1}{3}\))+(4−\(\frac{3}{2}\)−\(\frac{1}{3}\))−(2−\(\frac{3}{8}\)−\(\frac{1}{24}\))=\(\frac{17}{6}\)
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,
The theory that is part of mathematics is the approximation theory. An approximation is employed when it becomes difficult to seek out the exact value of any number. It is also essential to round off the errors resulting in approximation.
In general, the wavy equal “≈” sign is used to represent the approximate values that stand for “almost equal to”.
For Example ⇢ π ≈ 3.14
Consider y = f(x) = any function of x.
Let,
Δx = the small change in x
Δy = the corresponding change in y


Here are some of the essential points that are required to be remembered: