The given equation for \(y\) is \(y = |x - 1| + |x - 2|\). The graph of \(y\)intersects the line \(y = 3\) at certain points, forming a bounded area.

The area can be calculated by finding the points of intersection of the curves and calculating the area between them. After calculating, we find the area is 4 square units.
The area of the region given by \(\left\{(x, y): x y \leq 8,1 \leq y \leq x^2\right\}\) is :
If 5f(x) + 4f (\(\frac{1}{x}\)) = \(\frac{1}{x}\)+ 3, then \(18\int_{1}^{2}\) f(x)dx is:
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
Read More: Area under the curve formula