Given:
Magnitude of first earthquake: \(M_1 = 5\)
Amplitude at station: \(A_1 = x\)
Amplitude of second earthquake: \(A_2 = 15x\)
We need \(M_2\).
Step 1 — Use Richter magnitude formula:
\[ M = \log_{10}\frac{A}{A_0} \] where \(A_0\) is a reference amplitude (same for both, so it cancels in difference). Difference in magnitude: \[ M_2 - M_1 = \log_{10}\frac{A_2}{A_1} \]
Step 2 — Plug in values:
\[ M_2 - 5 = \log_{10}\frac{15x}{x} = \log_{10}15 \] \[ \log_{10} 15 \approx 1.1761 \] \[ M_2 = 5 + 1.1761 \approx 6.18 \] Answer (rounded to two decimals): \(\boxed{6.18}\)
| Group I | Group II | ||
| P | Iceland | 1 | Subduction Zone |
| Q | Indonesia | 2 | Transform Fault |
| R | Nepal | 3 | Mid-Oceanic Ridge |
| S | New Zealand | 4 | Continental Collision |