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the acceleration of any electron due to the magnet
Question:
The acceleration of any electron due to the magnetic field is
BCECE - 2010
BCECE
Updated On:
Nov 4, 2024
$3.14\times10^{14} \,m/s^2$
$4.28\times10^{14} \,m/s^2$
$5.56\times10^{12}\, m/s^2$
$6.28\times10^{14}\, m/s^2$
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The Correct Option is
D
Solution and Explanation
Answer (d)
$6.28\times10^{14}\, m/s^2$
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