The absolute value of the electron gain enthalpy of halogens satisfies :
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- \(\mathrm{Cl}\gt\mathrm{Br}\gt\mathrm{F}\gt\mathrm{I}\)
- \(\mathrm{Cl}\gt\mathrm{F}\gt\mathrm{Br}\gt\mathrm{I}\)
- \(\mathrm{I}\gt\mathrm{Br}\gt\mathrm{Cl}\gt\mathrm{F}\)
- \(\mathrm{F}\gt\mathrm{Cl}\gt\mathrm{Br}\gt\mathrm{I}\)
The Correct Option is B
Solution and Explanation
Absolute values therefore follow Cl > F > Br > I.
F is out of order because the very small 2p subshell causes strong electron-electron repulsion for the incoming electron.
Answer: (2) \(\mathrm{Cl}\gt\mathrm{F}\gt\mathrm{Br}\gt\mathrm{I}\)
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