Let a be the first term and r be the common ratio of the G.P.
∴ a = -3
It is known that, an = \(arn^-1\)
∴\(a^4\) = a\(r^3\)= (-3) \(r^3\)
\(a^2\) = a \(r^1\)= (-3) r
According to the given condition,
(-3) \(r^3\) = [(-3) r\(]^2\)
⇒ -3\(r^3\)= 9 \(r^2\)
⇒ r = -3
\(a^7\) = a\(r^7-1\)
= a \(r^6\)
= (-3) (-3\()^6\)
= - (3\()^7\)
= -2187
Thus, the seventh term of the G.P. is -2187.
\(f(x) = \begin{cases} x^2, & \quad 0≤x≤3\\ 3x, & \quad 3≤x≤10 \end{cases}\)
The relation g is defined by
\(g(x) = \begin{cases} x^2, & \quad 0≤x≤2\\ 3x, & \quad 2≤x≤10 \end{cases}\)
Show that f is a function and g is not a function.