The 2×2 matrices P and Q satisfy the following relations: 
The matrix Q is equal to _______.
A
B
C
D
\[ (P + Q) + (P - Q) = \begin{pmatrix} 3 & 1 \\ 2 & 12 \end{pmatrix} + \begin{pmatrix} -1 & -7 \\ 8 & 2 \end{pmatrix}. \]
This simplifies to:\[ 2P = \begin{pmatrix} 2 & -6 \\ 10 & 14 \end{pmatrix}. \]
Thus,\[ P = \frac{1}{2} \begin{pmatrix} 2 & -6 \\ 10 & 14 \end{pmatrix} = \begin{pmatrix} 1 & -3 \\ 5 & 7 \end{pmatrix}. \]
Now, subtract \( P - Q \) from \( P + Q \):\[ (P + Q) - (P - Q) = \begin{pmatrix} 3 & 1 \\ 2 & 12 \end{pmatrix} - \begin{pmatrix} -1 & -7 \\ 8 & 2 \end{pmatrix}. \]
This gives:\[ 2Q = \begin{pmatrix} 4 & 8 \\ -6 & 10 \end{pmatrix}, \]
so\[ Q = \frac{1}{2} \begin{pmatrix} 4 & 8 \\ -6 & 10 \end{pmatrix} = \begin{pmatrix} 2 & 4 \\ -3 & 5 \end{pmatrix}. \]
Thus, the correct answer is (A).\[ \boxed{(A)\, \begin{pmatrix} 2 & 4 \\ -3 & 5 \end{pmatrix}.} \]