$\textbf{Match List I with List II}$
$\begin{array}{|c|c|c|} \hline \text{List I (Compound)} & \text{List II (p}K_a\text{ value)} \\ \hline \text{A. Ethanol} & \text{I. } 10.0 \\ \text{B. Phenol} & \text{II. } 15.9 \\ \text{C. m-Nitrophenol} & \text{III. } 7.1 \\ \text{D. p-Nitrophenol} & \text{IV. } 8.3 \\ \hline \end{array}$
$\text{Choose the correct answer from the options given below :-}$
$\begin{array}{|c|c|c|} \hline \text{List I (Compound)} & \text{List II (p}K_a\text{ value)} \\ \hline \text{A. Ethanol} & \text{I. } 10.0 \\ \text{B. Phenol} & \text{II. } 15.9 \\ \text{C. m-Nitrophenol} & \text{III. } 7.1 \\ \text{D. p-Nitrophenol} & \text{IV. } 8.3 \\ \hline \end{array}$
$\text{Choose the correct answer from the options given below :-}$
- A-I, B-II, C-III, D-IV
- A-IV, B-I, C-II, D-III
- A-III, B-IV, C-I, D-II
- A-II, B-I, C-IV, D-III
The Correct Option is D
Approach Solution - 1
To solve the question, we need to match the given compounds in List I with their respective \(pK_a\) values in List II. The \(pK_a\) value is a measure of the acidity of a compound; a lower value indicates stronger acidity.
- Understanding the Compounds and their Acidity:
- Ethanol: Ethanol is a simple alcohol and relatively weaker acid compared to phenols. It generally has a higher \(pK_a\) value.
- Phenol: Phenol is more acidic than ethanol due to the resonance stabilization of the phenoxide ion formed after losing a proton. It typically has a lower \(pK_a\) value compared to ethanol.
- m-Nitrophenol and p-Nitrophenol: Both of these compounds are nitrophenol derivatives, where the nitro group, an electron-withdrawing group, increases the acidity further. Among nitrophenols, the para derivative typically has a lower \(pK_a\) due to stronger electron-withdrawing effects.
- Matching the \(pK_a\) Values:
- Ethanol: The \(pK_a\) value for ethanol is around 15.9.
- Phenol: Typically, the \(pK_a\) value for phenol is around 10.0.
- m-Nitrophenol: The \(pK_a\) value for m-nitrophenol is around 8.3.
- p-Nitrophenol: The \(pK_a\) value for p-nitrophenol is around 7.1.
- Conclusion: Based on the above analysis, we can match the compounds with their respective \(pK_a\) values:
- A. Ethanol - II. 15.9
- B. Phenol - I. 10.0
- C. m-Nitrophenol - IV. 8.3
- D. p-Nitrophenol - III. 7.1
Approach Solution -2
The correct matching is as follows:
- A. Ethanol has a \( pK \) value of 15.9, so \( A - II \).
- B. Phenol has a \( pK \) value of 10.0, so \( B - I \).
- C. \( m \)-Nitrophenol has a \( pK \) value of 8.3, so \( C - IV \).
- D. \( p \)-Nitrophenol has a \( pK \) value of 7.1, so \( D - III \).
Hence, the correct matching is \( A - II, B - I, C - IV, D - III \).
The Correct Answer is: A-II, B-I, C-IV, D-III
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