Step 1: Use the identity \( \tan(90^\circ - \theta) = \cot(\theta) \).
Thus, \( \tan 85^\circ = \cot 5^\circ \) and \( \tan 65^\circ = \cot 25^\circ \).
Step 2: The expression becomes:
\[
\tan 5^\circ \cdot \tan 25^\circ \cdot \tan 30^\circ \cdot \cot 25^\circ \cdot \cot 5^\circ = \tan 30^\circ
\]
Step 3: Simplify:
\[
\tan 30^\circ = \frac{1}{\sqrt{3}}
\]
Thus, the correct answer is \( \boxed{\frac{1}{\sqrt{3}}} \).