Sum of bond order of CO and NO+ is _____.
Correct Answer: 6
Approach Solution - 1
To find the sum of the bond orders of CO and NO+, we start by determining each bond order individually.
Bond Order of CO:
- The bond order of a molecule is calculated using the molecular orbital theory. For CO, it has 10 valence electrons.
- The electronic configuration in terms of molecular orbitals is: (σ1s)2(σ*1s)2(σ2s)2(σ*2s)2(π2p)4(σ2p)2.
- Bond order = (Number of electrons in bonding orbitals - Number of electrons in antibonding orbitals) / 2.
- Bond order of CO: (8-2)/2 = 3.
Bond Order of NO+:
- NO+ has 10 valence electrons since it is derived from NO by losing an electron.
- Its electronic configuration is similar to that of CO.
- Therefore, its bond order calculation is the same as CO.
- Bond order of NO+: (8-2)/2 = 3.
Sum of Bond Orders:
- Sum = Bond order of CO + Bond order of NO+ = 3 + 3 = 6.
Verification:
- The calculated sum is 6. This fits precisely within the provided range of 6 to 6.
Thus, the sum of the bond orders of CO and NO+ is 6.
Approach Solution -2
- CO: Bond order of CO is 3, as it has a triple bond structure (C ≡ O).
- NO+: Bond order of NO+ is also 3 (N ≡ O+).
Thus, the sum of the bond orders is:
3 + 3 = 6
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