Question

Sum of bond order of CO and NO⁺ is _____.

Answer 1

Correct Answer: 6

To find the sum of the bond orders of CO and NO⁺, we start by determining each bond order individually.

Bond Order of CO: 

• The bond order of a molecule is calculated using the molecular orbital theory. For CO, it has 10 valence electrons.
• The electronic configuration in terms of molecular orbitals is: (σ_1s)²(σ^*_1s)²(σ_2s)²(σ^*_2s)²(π_2p)⁴(σ_2p)².
• Bond order = (Number of electrons in bonding orbitals - Number of electrons in antibonding orbitals) / 2.
• Bond order of CO: (8-2)/2 = 3.

Bond Order of NO⁺:

• NO⁺ has 10 valence electrons since it is derived from NO by losing an electron.
• Its electronic configuration is similar to that of CO.
• Therefore, its bond order calculation is the same as CO.
• Bond order of NO⁺: (8-2)/2 = 3.

Sum of Bond Orders:

• Sum = Bond order of CO + Bond order of NO⁺ = 3 + 3 = 6.

Verification:

• The calculated sum is 6. This fits precisely within the provided range of 6 to 6.

Thus, the sum of the bond orders of CO and NO⁺ is 6.

Answer 2

- CO: Bond order of CO is 3, as it has a triple bond structure (C ≡ O).
- NO⁺: Bond order of NO⁺ is also 3 (N ≡ O⁺).
Thus, the sum of the bond orders is:
3 + 3 = 6