Structures of four disaccharides are given below. Among the given disaccharides, the non-reducing sugar is: 
Concept: Reducing sugars are those which have a free anomeric carbon atom (free \(-OH\) group on the hemiacetal carbon) that can open up to form an aldehyde or ketone group, allowing them to reduce reagents like Tollen’s or Fehling’s solution. Non-reducing sugars lack a free anomeric carbon because both anomeric carbons are involved in glycosidic linkage.
Step 1: Analyze each disaccharide.
- \(\mathbf{Maltose}\): Formed from two glucose units with \(\alpha(1 \to 4)\) linkage. One anomeric carbon is free → reducing sugar.
- \(\mathbf{Lactose}\): Formed from glucose and galactose with \(\beta(1 \to 4)\) linkage. One anomeric carbon is free → reducing sugar.
- \(\mathbf{Sucrose}\): Formed from glucose and fructose with \(\alpha(1 \to 2)\) and \(\beta(2 \to 1)\) linkage. Both anomeric carbons are involved in glycosidic bond → non-reducing sugar.
- \(\mathbf{Cellobiose}\): Formed from two glucose units with \(\beta(1 \to 4)\) linkage. One anomeric carbon is free → reducing sugar.
Step 2: Conclusion. Among the given disaccharides, sucrose is the only non-reducing sugar. \[ \text{Answer: Sucrose (Option 3)} \]
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
The cyclic cations having the same number of hyperconjugation are:
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)