Structures of four disaccharides are given below. Among the given disaccharides, the non-reducing sugar is: 
Concept: Reducing sugars are those which have a free anomeric carbon atom (free \(-OH\) group on the hemiacetal carbon) that can open up to form an aldehyde or ketone group, allowing them to reduce reagents like Tollen’s or Fehling’s solution. Non-reducing sugars lack a free anomeric carbon because both anomeric carbons are involved in glycosidic linkage.
Step 1: Analyze each disaccharide.
- \(\mathbf{Maltose}\): Formed from two glucose units with \(\alpha(1 \to 4)\) linkage. One anomeric carbon is free → reducing sugar.
- \(\mathbf{Lactose}\): Formed from glucose and galactose with \(\beta(1 \to 4)\) linkage. One anomeric carbon is free → reducing sugar.
- \(\mathbf{Sucrose}\): Formed from glucose and fructose with \(\alpha(1 \to 2)\) and \(\beta(2 \to 1)\) linkage. Both anomeric carbons are involved in glycosidic bond → non-reducing sugar.
- \(\mathbf{Cellobiose}\): Formed from two glucose units with \(\beta(1 \to 4)\) linkage. One anomeric carbon is free → reducing sugar.
Step 2: Conclusion. Among the given disaccharides, sucrose is the only non-reducing sugar. \[ \text{Answer: Sucrose (Option 3)} \]
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
The cyclic cations having the same number of hyperconjugation are:
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,