Question:

Statement I: Of the following compounds \( SO_2, SO_3, H_2S, SF_4 \); only three compounds have a complete octet.
Statement II: For the given set of compounds \([SF_4, BrF_5, ClF_3], [NH_3, BrF_5, SF_4], [H_2O, IF_5, XeF_4]\) only one set of compounds has one lone pair on all central atoms.

Show Hint

In molecules like \( SF_4 \), \( BrF_5 \), and \( ClF_3 \), pay attention to the number of lone pairs on the central atom when determining the octet rule and lone pair distribution.
Updated On: Apr 7, 2026
  • Both Statement I and Statement II are correct
  • Statement I is incorrect but Statement II is correct
  • Statement I is correct but Statement II is incorrect
  • Both Statement I and Statement II are incorrect
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The Correct Option is B

Solution and Explanation

Step 1: Analysis of Statement I.
- \( SO_2 \) has 8 electrons around sulfur (complete octet).
- \( SO_3 \) has 8 electrons around sulfur (complete octet).
- \( H_2S \) has 8 electrons around sulfur (complete octet).
- \( SF_4 \) has 10 electrons around sulfur (not a complete octet). Hence, only three compounds, \( SO_2, SO_3, H_2S \), have a complete octet. Therefore, Statement I is incorrect because \( SF_4 \) does not have a complete octet.

Step 2:
Analysis of Statement II.
Let's examine the lone pairs on the central atoms of the given compounds: - \( SF_4 \) has 1 lone pair on the central atom (sulfur).
- \( BrF_5 \) has 1 lone pair on the central atom (bromine).
- \( ClF_3 \) has 2 lone pairs on the central atom (chlorine).
- \( NH_3 \) has 1 lone pair on nitrogen.
- \( BrF_5 \) has 1 lone pair on the central atom (bromine).
- \( SF_4 \) has 1 lone pair on the central atom (sulfur).
- \( H_2O \) has 2 lone pairs on oxygen.
- \( IF_5 \) has 1 lone pair on iodine.
- \( XeF_4 \) has 2 lone pairs on xenon.
Thus, only the set \([SF_4, BrF_5, SF_4]\) has 1 lone pair on all central atoms. Therefore, Statement II is correct.
Final Answer: (B) Statement I is incorrect but Statement II is correct
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