Question:
Starting from (–1) × 5, write various products showing some pattern to show (–1) × (–1) = 1.
Starting from (–1) × 5, write various products showing some pattern to show (–1) × (–1) = 1.
Updated On: Jun 24, 2025
Show Solution
Verified By Collegedunia
Solution and Explanation
(-1) × 5 = -5
(-1) × 4 = -4 = (-5) + 1
(-1) × 3 = -3 = (-4) + 1
(-1) × 2 = -2 = (-3) + 1
(-1) × (1) = -1 = (-2) + 1
(-1) × 0 = 0 – (-1) + 1
(-1) × (-1) = 1 = 0 + 1
Was this answer helpful?
2
0
Top CBSE Class VII Mathematics Questions
- Find the area of each of the following parallelograms:
- Find the area of each of the following triangles:
- Find the missing values:
So No Base Height Area of parallelogram a. 20 cm - 246 \(cm^2\) b. - 15 cm 154.5 \(cm^2\) c. - 8.4 cm 48.72 \(cm^2\) d. 15.6 cm - 16.38 \(cm^2\) - Find the missing values:
Base Height Area of triangle 15 cm - 87 \(cm^2\) - 31.4 mm 1256 \(mm^2\) 22 cm - 170.5 \(cm^2\) - PQRS is a parallelogram (see the given figure). QM is the height from Q to SR and QN is the height from Q to PS. If SR = \(12\) cm and QM = \(7.6\) cm. Find:
- the area of the parallelogram PQRS
- QN, if PS = 8 cm
View More Questions
Top CBSE Class VII Properties Of Multiplication Of Integers Questions
- Find each of the following products:
(a) 3 × (–1)
(b) (–1) × 225
(c) (–21) × (–30)
(d) (–316) × (–1)
(e) (–15) × 0 × (–18)
(f) (–12) × (–11) × (10)
(g) 9 × (–3) × (– 6)
(h) (–18) × (–5) × (– 4)
(i) (–1) × (–2) × (–3) × 4
(j) (–3) × (–6) × (–2) × (–1) - Verify the following:
(a) 18 × [ 7 + (–3)] = [18 × 7] + [18 × (–3)]
(b) (–21) × [(– 4) + (– 6)] = [(–21) × (– 4)] + [(–21) × (– 6)] - (i) For any integer a, what is (–1) × a equal to?
(ii) Determine the integer whose product with (–1) is
(a) –22
(b) 37
(c) 0
Top CBSE Class VII Questions
- Find the area of each of the following parallelograms:
- Find the area of each of the following triangles:
- Find the missing values:
So No Base Height Area of parallelogram a. 20 cm - 246 \(cm^2\) b. - 15 cm 154.5 \(cm^2\) c. - 8.4 cm 48.72 \(cm^2\) d. 15.6 cm - 16.38 \(cm^2\) - Find the missing values:
Base Height Area of triangle 15 cm - 87 \(cm^2\) - 31.4 mm 1256 \(mm^2\) 22 cm - 170.5 \(cm^2\) - PQRS is a parallelogram (see the given figure). QM is the height from Q to SR and QN is the height from Q to PS. If SR = \(12\) cm and QM = \(7.6\) cm. Find:
- the area of the parallelogram PQRS
- QN, if PS = 8 cm
View More Questions