\[
\sqrt{\frac{64}{81}} + \sqrt{\frac{16}{9}} = \frac{\sqrt{64}}{\sqrt{81}} + \frac{\sqrt{16}}{\sqrt{9}}.
\]
\[
= \frac{8}{9} + \frac{4}{3}.
\]
Converting to a common denominator:
\[
= \frac{8}{9} + \frac{12}{9} = \frac{20}{9}.
\]
Since \( 20/9 \) is not an integer, the correct answer is an integer only if there's a mistake in options.