The correct answer is 6
[MnBr6]–4
x – 6 = –4
x = + 2 Mn = 3d54s2
Mn+2 = 3d54s0
n = 5
\(μ = \sqrt{n(n+2)}\)
\(= \sqrt{35} ≈ 6 B.M.\)


| Column-I (Complex compound) | Column-II ($\Delta_0$ (CFSE) $\text{cm}^{-1}$) |
| (i) $[Cr(CN)_6]^{3-}$ | (P) 17000 |
| (ii) $[Cr(H_2O)_6]^{3+}$ | (Q) 15000 |
| (iii) $[Cr(en)_3]^{3+}$ | (R) 12000 |
| (iv) $[CrF_6]^{3-}$ | (S) 20000 |

The value of \[ \int_0^{2} \sqrt{\frac{x(x^2+x+1)}{(x+1)(x^4+x^2+1)}} \, dx \] is
A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.
A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.
A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.