Question:

Spin only magnetic moment of an octahedral complex of \(\mathrm{Fe^{2+}}\) in the presence of a strong field ligand in BM is :

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\(\mathrm{Fe^{2+}}\) is \(d^6\); with a strong field ligand it is low spin (\(t_{2g}^6 e_g^0\)) with no unpaired electrons.
Updated On: Nov 4, 2026
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The Correct Option is C

Solution and Explanation

\(\mathrm{Fe^{2+}}\): \([\mathrm{Ar}]3d^6\).
A strong field ligand gives a large \(\Delta_o\) so electrons pair up in \(t_{2g}\): \(t_{2g}^6 e_g^0\), unpaired electrons n = 0.
\(\mu = \sqrt{n(n+2)} = 0\) BM.
Answer: (3) 0
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