From \( 3x + 2y = 4 \):
\[
y = \frac{4 - 3x}{2}
\]
Substituting in \( 8x + 5y = 9 \):
\[
8x + 5\left(\frac{4 - 3x}{2}\right) = 9
\]
\[
16x + 20 - 15x = 18
\]
\[
x = -2
\]
Substituting \( x = -2 \) in \( y = \frac{4 - 3x}{2} \):
\[
y = \frac{4 - 3(-2)}{2} = \frac{4 + 6}{2} = 5
\]
Thus, \( x = \mathbf{-2}, y = \mathbf{5} \).
Correct Answer: \( x = -2, y = 5 \)