The osmotic pressure (\( \pi \)) for a solution is given by the formula:
\[ \pi = \frac{nRT}{V} \] where:
\( n \) is the number of moles of solute,
\( R \) is the gas constant,
\( T \) is the temperature,
\( V \) is the volume of the solution.
For non-electrolyte (A) and glucose, the osmotic pressures are the same, so we can equate the osmotic pressures: \[ \frac{12 / M_A}{1} = 0.05 \times 1 \] where \( M_A \) is the molar mass of A, and 12 g is the mass of A. Simplifying the equation: \[ \frac{12}{M_A} = 0.05 \quad \Rightarrow \quad M_A = \frac{12}{0.05} = 240 \, \text{g/mol}. \] Thus, the molecular mass of A is 240 g/mol.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)