Step 1: Understanding the Question:
The question asks us to identify the classification of the salt formed by the neutralization reaction of the acid present in vinegar with a sodium-containing base.
Step 2: Key Formula or Approach:
We must identify the chemical constituents of vinegar and determine the strengths of the acid and base required to synthesize its sodium salt.
Step 3: Detailed Explanation:
• The acid present in vinegar is acetic acid (\(CH_3COOH\)), which is also systematically named as ethanoic acid.
• Acetic acid is a weak organic acid because it only partially dissociates into ions when dissolved in water:
\[ CH_3COOH\text{(aq)} \rightleftharpoons CH_3COO^-\text{(aq)} + H^+\text{(aq)} \]
• The sodium salt of this acid is sodium acetate (\(CH_3COONa\)).
• Sodium acetate is chemically prepared by reacting acetic acid (a weak acid) with sodium hydroxide (\(NaOH\)), which is a strong, highly soluble mineral base:
\[ CH_3COOH\text{(aq)} + NaOH\text{(aq)} \to CH_3COONa\text{(aq)} + H_2O\text{(l)} \]
• Since this salt is synthesized from a weak acid (\(CH_3COOH\)) and a strong base (\(NaOH\)), it is classified as a "salt of a weak acid and a strong base."
• Due to the dominance of the strong base conjugate, an aqueous solution of sodium acetate undergoes anionic hydrolysis to yield a basic solution with a pH value greater than 7:
\[ CH_3COO^-\text{(aq)} + H_2O\text{(l)} \rightleftharpoons CH_3COOH\text{(aq)} + OH^-\text{(aq)} \]
Step 4: Final Answer:
The sodium salt of the acid in vinegar is an example of a salt of a weak acid + strong base.