Let \(A ⊂ B \)
To show: \(C – B ⊂ C – A \)
Let \(x ∈ C – B \)
\(⇒ x ∈ C\) and \(x ∉ B \)
\(⇒ x ∈ C \) and \(x ∉ A [A ⊂ B] \)
\(⇒ x ∈ C – A \)
\(∴ C – B ⊂ C – A\)
\(f(x) = \begin{cases} x^2, & \quad 0≤x≤3\\ 3x, & \quad 3≤x≤10 \end{cases}\)
The relation g is defined by
\(g(x) = \begin{cases} x^2, & \quad 0≤x≤2\\ 3x, & \quad 2≤x≤10 \end{cases}\)
Show that f is a function and g is not a function.
Some important operations on sets include union, intersection, difference, and the complement of a set, a brief explanation of operations on sets is as follows:
1. Union of Sets:
2. Intersection of Sets:
3.Set Difference:
4.Set Complement: