Let's solve this problem step-by-step. We need to determine Sheela's overall profit when she buys two varieties of apples and sells them at certain profit percentages.
\(5k \times 1.2x + 8k \times x = 2800\) (Equation 1).
\(6kx + 8kx = 2800\)
\(14kx = 2800\)
Solve for \(kx\):
\(kx = \frac{2800}{14} = 200\) (Equation 2)
The total cost of variety A (5k kg):
\(5k \times 1.2x = 6kx = 6 \times 200 = 1200\) Rupees.
The total cost of variety B (8k kg):
\(8k \times x = 8kx = 8 \times 200 = 1600\) Rupees.
Profit on variety A:
\(0.15 \times 1200 = 180\) Rupees.
Profit on variety B:
\(0.10 \times 1600 = 160\) Rupees.
Total profit = Profit on A + Profit on B = \(180 + 160 = 340\) Rupees.
Thus, the overall profit is 340 Rupees. The correct answer is 340.
Let's solve the problem step by step:
Step 1: Determine the weights of A and B.
Let the weights of apples A and B be 5x and 8x respectively, based on their ratio of 5:8.
Step 2: Understand the cost per kg relationship.
Let the cost per kg of apple B be Rs y. Therefore, the cost per kg of apple A will be Rs 1.2y (20% more than B).
Step 3: Formulate the equation based on total cost.
5x * 1.2y + 8x * y = 2800
Therefore, 6xy + 8xy = 2800
So, 14xy = 2800
Thus, xy = 200
Step 4: Calculate the profit Sheela earns from each type of apple.
Sheela earns a 15% profit on A and a 10% profit on B. Calculating the selling prices:
Add the selling prices to find the total selling price:
Total selling price = 5x * 1.2y * 1.15 + 8x * y * 1.1
Total selling price = 5x * 1.38y + 8x * 1.1y
Total selling price = 6.9xy + 8.8xy
Total selling price = 15.7xy
Given xy = 200, the total selling price is 15.7 * 200 = 3140.
Step 5: Determine the overall profit.
Overall profit = Total selling price - Total cost price
Overall profit = 3140 - 2800 = 340
Conclusion: The overall profit is Rs 340.