We start with the expression:
\[
x + yz.
\]
Check each option for equivalence:
(B)
\[
(x + y)(x + z)
\]
Using Boolean algebra:
\[
(x + y)(x + z) = x + yz,
\]
so (B) is equivalent.
(C)
\[
x + xy + yz = x(1 + y) + yz = x + yz,
\]
because $1 + y = 1$.
Thus (C) is equivalent.
(A) produces unwanted term $z$ when $x=0$, $z=1$.
(D) contains $xz$ which incorrectly enlarges the function.
Hence the correct answers are (B) and (C).
Final Answer: (B), (C)