
The synthesis of salicylaldehyde from phenol can be achieved through the reaction of phenol with HCl and NaOH in a method known as the Reimer-Tiemann reaction. Here’s how the reaction proceeds:
Reimer-Tiemann Reaction: In this reaction, phenol is treated with chloroform in the presence of a strong base (usually NaOH) and HCl is used for the acidic work-up.
The phenol undergoes electrophilic substitution, resulting in the ortho- and para-formylation of the aromatic ring.
Reaction Overview: The reaction mechanism involves:
Final Product: The final product is salicylaldehyde, which can be represented as follows:
\(\text{Phenol} + \text{Chloroform} \xrightarrow{\text{NaOH}} \text{Salicylaldehyde}\)
Salicylaldehyde is synthesized from phenol. The correct reagents for this synthesis must be identified from the given options.
The Reimer-Tiemann reaction is a key organic conversion used to synthesize ortho-hydroxybenzaldehydes (such as salicylaldehyde) from phenols. The reaction involves the treatment of phenol with chloroform (CHCl₃) in the presence of a strong base like sodium hydroxide (NaOH).
Step 1: Identify the target compound and the starting material. The target is salicylaldehyde (2-hydroxybenzaldehyde), and the starting material is phenol.
Step 2: Recall the standard reagent combination for the Reimer-Tiemann reaction. The reagents are chloroform (CHCl₃) and a strong base (NaOH).
Step 3: Compare the standard reagents with the given options.
Option (1): HCl, NaOH - This is not the correct combination for introducing an aldehyde group.
Option (2): CO₂, NaOH - This is the Kolbe-Schmitt reaction, which produces salicylic acid, not salicylaldehyde.
Option (3): CCl₄, NaOH - This can produce salicylic acid under specific conditions, not the aldehyde.
Option (4): HCCl₃, NaOH - This represents chloroform (CHCl₃) and sodium hydroxide, which is the exact reagent combination for the Reimer-Tiemann reaction.
Therefore, salicylaldehyde is synthesized from phenol using the reagents in Option (4): HCCl₃, NaOH.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are


What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,