Question:

Raju got married 8 years ago. His present age is \( \frac{6}{5} \) times his age at the time of his marriage. Raju's sister was 10 years younger than him at the time of his marriage. The present age of Raju's sister is?

Updated On: May 6, 2026
  • \(30\) years
  • \(35\) years
  • \(38\) years
  • \(36\) years
  • \(40\) years
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The Correct Option is C

Solution and Explanation


Concept: This is an
age problem involving:
  • Relation between present and past ages
  • Constant age difference

Step 1: Assume age at marriage.
Let Raju's age at marriage be \(x\).
Present age \(= x + 8\)
Step 2: Use given relation.
\[ x + 8 = \frac{6}{5}x \]
Step 3: Solve equation.
\[ 5x + 40 = 6x \Rightarrow x = 40 \]
Step 4: Find present age of Raju.
\[ \text{Present age} = 40 + 8 = 48 \]
Step 5: Find sister's age.
At marriage, sister was: \[ 40 - 10 = 30 \] Present age: \[ 30 + 8 = 38 \]
Step 6: Option analysis.
  • (A) 30: Past age $\times$
  • (B) 35: Incorrect $\times$
  • (C) 38: Correct \checkmark
  • (D) 36: Incorrect $\times$
  • (E) 40: Incorrect $\times$

Conclusion:
Thus, the correct answer is
Option (C).
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