Question:

Quantity of air to be circulated to underground workings where \(150\) workers are employed in a largest shift and daily production is \(500\) t will be

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Mine ventilation quantity is the greater of \[ \boxed{ 6\ \mathrm{m^3/min\ per\ person} \quad\text{or}\quad 2.5\ \mathrm{m^3/min\ per\ tonne/day}. } \]
Updated On: Jul 14, 2026
  • \(900\ \mathrm{m^3/min}\)
  • \(900\ \mathrm{m^3/s}\)
  • \(1250\ \mathrm{m^3/min}\)
  • \(1250\ \mathrm{m^3/s}\)
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The Correct Option is C

Solution and Explanation

Step 1: Use the statutory ventilation requirements. The minimum quantity of air is taken as the greater of: \[ 6\ \mathrm{m^3/min} \] per person, or \[ 2.5\ \mathrm{m^3/min} \] per tonne of daily production.

Step 2:
Calculate both values. For \(150\) workers, \[ Q_1=150\times6=900\ \mathrm{m^3/min}. \] For \(500\) t/day production, \[ Q_2=500\times2.5=1250\ \mathrm{m^3/min}. \] Since the larger value is adopted, \[ Q=1250\ \mathrm{m^3/min}. \] Therefore, \[ \boxed{(C)} \] is the correct answer.
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