Step 1: Understanding the Concept:
The problem asks to compare two large products of consecutive integers. Calculating the full products is impractical. The best approach is to identify and cancel out common factors.
Step 2: Key Formula or Approach:
We will write out the expressions for both quantities and identify the overlapping sequence of numbers. By "dividing out" or canceling these common terms, we can reduce the comparison to a much simpler calculation.
Step 3: Detailed Explanation:
Let's write out the products for Quantity A and Quantity B.
Quantity A = \(20 \times 21 \times 22 \times \dots \times 71 \times 72 \times 73\)
Quantity B = \(18 \times 19 \times 20 \times 21 \times \dots \times 71 \times 72\)
Both quantities share the product of the integers from 20 to 72. Let's call this common product \(C\).
\[ C = 20 \times 21 \times \dots \times 72 \]
Now, we can express Quantity A and Quantity B in terms of \(C\).
Quantity A = \(C \times 73\)
Quantity B = \(18 \times 19 \times C\)
Since \(C\) is a product of positive integers, it is a large positive number. To compare Quantity A and Quantity B, we only need to compare their unique factors: 73 and \(18 \times 19\).
Let's calculate the product \(18 \times 19\):
\[ 18 \times 19 = 18 \times (20 - 1) = (18 \times 20) - (18 \times 1) = 360 - 18 = 342 \]
Now we compare the unique factors:
The unique factor for Quantity A is 73.
The unique factors for Quantity B multiply to 342.
Step 4: Final Answer:
We are comparing \(C \times 73\) with \(C \times 342\).
Since \(342 \textgreater 73\), and \(C\) is positive, it follows that \(C \times 342 \textgreater C \times 73\).
Therefore, Quantity B is greater than Quantity A.