Step 1: Let the two parts be $P$ and $2P$, so total $M = 3P$.
Step 2: One interest rate is 10%. Since the larger amount is in a scheme with half the rate, two cases are possible.
Step 3: Case 1: Smaller amount (P) at 10%, larger (2P) at 5%.
Interest after 2 years: $P(1.1^2 - 1) + 2P(1.05^2 - 1) = 830$.
$P(1.21 - 1) + 2P(1.1025 - 1) = 830$.
$P(0.21) + 2P(0.1025) = 830$.
$0.21P + 0.205P = 0.415P = 830 \implies P = 2000$.
Then $M = 3P = 6000$. Each deposit: $P=2000$, $2P=4000$, both >
1000. This works.
Step 4: Case 2: Smaller amount (P) at 5%, larger (2P) at 10%.
Interest: $P(1.05^2 - 1) + 2P(1.1^2 - 1) = 830$.
$P(0.1025) + 2P(0.21) = 830$.
$0.1025P + 0.42P = 0.5225P = 830 \implies P \approx 1588.5$.
Then $M \approx 4765.5$, not an options and also not matching the condition that one rate is 10% (both rates are 10% and 5% in this case, so it's valid but M is not in optionss).
Step 5: Since 6000 is in the optionss and satisfies all conditions, it is the correct answer.
Step 6: Final Answer: The value of M is 6000.