Step 1: Consider a concave mirror with an object placed at a distance \( u \) from the mirror, forming an image at \( v \). The focal length of the mirror is \( f \).
Using the geometry of the concave mirror and the laws of reflection, we apply the similar triangles method:
Step 2: Using the sign convention, we consider the two triangles formed:
\[
\triangle ABP \sim \triangle A'B'F
\]
\[
\frac{A'B'}{AB} = \frac{B'F}{BP}
\]
Similarly, using another set of similar triangles:
\[
\triangle A'B'P \sim \triangle OFB'
\]
\[
\frac{A'B'}{AB} = \frac{OF}{OP}
\]
Step 3: From these geometric relations, we derive the mirror formula:
\[
\frac{1}{v} + \frac{1}{u} = \frac{1}{f}
\]
Conclusion: The above derivation proves the mirror formula for a concave mirror.