Question

Polarization \( \vec{P} \) and electric susceptibility \( \chi \) are related as:

• A. \( \vec{P} = \epsilon_0 \chi \vec{E} \)
• B. \( \vec{P} = \frac{\chi}{\epsilon_0} \vec{E} \)
• C. \( \vec{P} = \chi \vec{E} \)
• D. \( \vec{P} = \frac{\epsilon_0}{\chi} \vec{E} \)

Hint:

Electric susceptibility \( \chi \) measures how easily a material gets polarized in response to an applied electric field.

Answer 1

The Correct Option is A

The relation between polarization \( \vec{P} \)** and **electric susceptibility \( \chi \) is: \[ \vec{P} = \epsilon_0 \chi \vec{E} \] where:
- \( \epsilon_0 \) is the permittivity of free space,
- \( \vec{E} \) is the applied electric field.