The given differential equation is:
\[
\frac{dy}{dx} = e^{x - y}
\]
Step 1: Rearranging the equation:
\[
\frac{dy}{dx} = e^x \cdot e^{-y}
\]
Step 2: Separating the variables:
\[
e^y \, dy = e^x \, dx
\]
Step 3: Integrating both sides:
\[
\int e^y \, dy = \int e^x \, dx
\]
Step 4: Performing the integrations:
\[
e^y = e^x + C
\]
Step 5: Taking the natural logarithm of both sides:
\[
y = \ln(e^x + C)
\]
Thus, the correct solution is \( y = \ln(e^x + C) \), which corresponds to option (A).