Negation of \( p \land (q \land \neg (p \land q)) \) is:}
To find the negation of the statement (¬p∧q)∨(p∧¬q), we will follow the steps of logical negation and apply De Morgan's laws.
1. Write down the original statement:
S=(¬p∧q)∨(p∧¬q)
2. Apply negation to the entire statement:
¬S=¬((¬p∧q)∨(p∧¬q))
3. Use De Morgan's Law: According to De Morgan's laws, the negation of a disjunction is the conjunction of the negations:
¬S=¬(¬p∧q)∧¬(p∧¬q)
4. Apply De Morgan's Law to each part:
¬(¬p∧q)=¬(¬p)∨¬(q)=p∨¬q
¬(p∧¬q)=¬(p)∨¬(¬q)=¬p∨q
5. Combine the results:
¬S=(p∨¬q)∧(¬p∨q)
6. Final expression:
The negation of the original statement is: ¬S=(p∨¬q)∧(¬p∨q)
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,