Question:

p-Hydroxybenzophenone upon reaction with bromine in carbon tetrachloride gives:

Show Hint

The OH group strongly activates its own ring towards electrophilic substitution (ortho to OH), while the C=O deactivates both rings.
Updated On: Nov 5, 2026
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

p-Hydroxybenzophenone: one ring has OH (strongly activating, ortho/para director) para to the C=O; the other ring is attached only to the deactivating C=O group.
Bromination in non-polar CCl\(_4\) is a mono-substitution electrophilic reaction; Br enters the activated ring. The para position of OH is blocked, so Br goes ortho to OH (position 3 with respect to the C=O).
This gives 3-bromo-4-hydroxybenzophenone, the structure in option (2) (Br next to OH on the same ring).
Answer: (2) 3-bromo-4-hydroxybenzophenone (Br ortho to the OH group)
Was this answer helpful?
0
0