Question

\( \overrightarrow{E} \) is the electric field inside a conductor whose material has conductivity \( \sigma \) and resistivity \( \rho \). The current density inside the conductor is \( \overrightarrow{j} \). The correct form of Ohm's law is

• A. \( \overrightarrow{E} = \sigma \overrightarrow{j} \)
• B. \( \overrightarrow{E} = \rho \overrightarrow{j} \)
• C. \( \overrightarrow{j} = \sigma \overrightarrow{E} \)
• D. \( \overrightarrow{j} = \rho \overrightarrow{E} \)

Answer 1

The Correct Option is C

Ohm’s law states that the current density \( \overrightarrow{j} \) is proportional to the electric field \( \overrightarrow{E} \), with the conductivity \( \sigma \) as the constant of proportionality: \[ \overrightarrow{j} = \sigma \overrightarrow{E} \] This expresses the relationship between the electric field and current density inside a conductor.