Outermost electronic configuration of a group 13 element, E, is \(4s^2, 4p^1\). The electronic configuration of an element of p-block period-five placed diagonally to element, E is :
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- [Kr] \(3d^{10}\) \(4s^2\) \(4p^2\)
- [Ar] \(3d^{10}\) \(4s^2\) \(4p^2\)
- [Xe] \(5d^{10}\) \(6s^2\) \(6p^2\)
- [Kr] \(4d^{10}\) \(5s^2\) \(5p^2\)
The Correct Option is D
Solution and Explanation
Diagonal relationship: the element one period down and one group to the right, i.e. period 5, group 14 = Sn.
Sn configuration: \(\mathrm{[Kr]\,4d^{10}\,5s^2\,5p^2}\).
(A) is not valid (Kr already contains 3d and 4s). (B) is Ge (period 4, same period as Ga). (C) is Pb (period 6).
Answer: (4) [Kr] \(4d^{10}\) \(5s^2\) \(5p^2\)
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