Question

One hundred kg paddy is dried from 18% wet basis to 13% wet basis moisture content. The amount of water removed (in kg) from the paddy is ________ (round off to one decimal place).

Hint:

To calculate the amount of water removed, use the difference in moisture content based on wet basis for the initial and final moisture levels.

Answer 1

Correct Answer: 5.5

We are given the following data:
- Initial weight of paddy = 100 kg
- Initial moisture content = 18%
- Final moisture content = 13%.
The amount of water removed can be calculated by using the formula for moisture content on a wet basis: \text{Water removed} = \left(\frac{\text{Initial moisture content}}{100 - \text{Initial moisture content}}\right) \times \text{Initial weight} - \left(\frac{\text{Final moisture content}}{100 - \text{Final moisture content}}\right) \times \text{Initial weight}. Substituting the values: \[ \text{Water removed} = \left(\frac{18}{100 - 18}\right) \times 100 - \left(\frac{13}{100 - 13}\right) \times 100 \] \[ = \left(\frac{18}{82}\right) \times 100 - \left(\frac{13}{87}\right) \times 100 \] \[ = 21.95 - 14.94 = 7.0 \, \text{kg}. \] Thus, the amount of water removed is 7.0 kg.