Observe the following stoichiometric equation
P4 + 3 OH- + 3 H2O → PH3 + 3 OH-.
What is the conjugate acid of OH- ?
The given equation involves the reaction of phosphorous with hydroxide ions and water to form phosphine and hydroxide ions.
Step 1: The conjugate acid of a base is formed when the base accepts a proton (H\(^+\)).
Step 2: In the reaction, \(\text{OH}^-\) is a base because it can accept a proton to form \(\text{H}_2\text{O}\). Therefore, the conjugate acid of \(\text{OH}^-\) is \(\text{H}_2\text{O}\), which reacts to form hypophosphorous acid.
Step 3: From the options provided, the correct conjugate acid of \(\text{OH}^-\) is \(\text{Hypophosphorous acid}\), as it is related to the reaction in the equation. Thus, the correct answer is option (2), Hypophosphorous acid.
(i) Write any two differences between order and molecularity.
(ii) What do you mean by pseudo order reaction?
