Number of unpaired electron in highest occupied molecular orbital of following species is :\(N_2, N ^+_ 2 , O_2, O^+_ 2 \) ?
For molecular species, determine the number of unpaired electrons using the molecular orbital theory. Focus on the HOMO.
0, 1, 2, 1
2, 1, 2, 1
0, 1, 0, 1
2, 1, 0, 1
Molecular Orbital Configurations:
\(N_2\): The molecular orbital configuration is:
\[\sigma(1s)^2 \, \sigma^*(1s)^2 \, \sigma(2s)^2 \, \sigma^*(2s)^2 \, \pi(2p_x)^2 \, \pi(2p_y)^2\]
Here, the highest occupied molecular orbital (HOMO) is \(\pi(2p_x)^2 \, \pi(2p_y)^2\) with no unpaired electrons.
\[\text{Unpaired electrons in } \text{N}_2 = 0.\]
\(N_2^+\): The configuration is:
\[\sigma(1s)^2 \, \sigma^*(1s)^2 \, \sigma(2s)^2 \, \sigma^*(2s)^2 \, \pi(2p_x)^2 \, \pi(2p_y)^1\]
The HOMO is \(\pi(2p_y)^1\) with 1 unpaired electron.
\[\text{Unpaired electrons in } \text{N}_2^+ = 1.\]
\(O_2\): The configuration is:
\[\sigma(1s)^2 \, \sigma^*(1s)^2 \, \sigma(2s)^2 \, \sigma^*(2s)^2 \, \pi(2p_x)^2 \, \pi(2p_y)^2 \, \pi^*(2p_x)^1 \, \pi^*(2p_y)^1\]
The HOMO is \(\pi^*(2p_x)^1 \, \pi^*(2p_y)^1\) with 2 unpaired electrons.
\[\text{Unpaired electrons in } \text{O}_2 = 2.\]
\(O_2^-\): The configuration is:
\[\sigma(1s)^2 \, \sigma^*(1s)^2 \, \sigma(2s)^2 \, \sigma^*(2s)^2 \, \pi(2p_x)^2 \, \pi(2p_y)^2 \, \pi^*(2p_x)^2 \, \pi^*(2p_y)^1\]
The HOMO is \(\pi^*(2p_y)^1\) with 1 unpaired electron.
\[\text{Unpaired electrons in } \text{O}_2^- = 1.\]
Thus, the number of unpaired electrons for \(\text{N}_2\), \(\text{N}_2^+\), \(\text{O}_2\), and \(\text{O}_2^-\) are {0, 1, 2, 1} respectively.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
Such a group of atoms is called a molecule. Obviously, there must be some force that holds these constituent atoms together in the molecules. The attractive force which holds various constituents (atoms, ions, etc.) together in different chemical species is called a chemical bond.
There are 4 types of chemical bonds which are formed by atoms or molecules to yield compounds.