Number of stereoisomers possible for the complexes, $\left[\mathrm{CrCl}_{3}(\mathrm{py})_{3}\right]$ and $\left[\mathrm{CrCl}_{2}(\mathrm{ox})_{2}\right]^{3-}$ are respectively} (py = pyridine, ox = oxalate)
To determine the number of stereoisomers for the given complexes, we need to consider the geometry and possible ligand arrangements around the central metal ion.
This complex is a coordination compound where chromium (Cr) is the central metal, coordinated by three chloride ions (Cl) and three pyridine molecules (py). This complex shows octahedral geometry because Cr is typically coordinated by six ligands in an octahedral shape.
For octahedral complexes of the type \([\text{MA}_3\text{B}_3]\), two types of isomerism can occur:
Thus, the complex \([\text{CrCl}_3(\text{py})_3]\) can exist as two stereoisomers: fac and mer.
The second complex involves chromium as a central metal ion, two chloride ions (Cl), and two oxalate ions (ox). Oxalate is a bidentate ligand, meaning each oxalate ligand coordinates to the metal at two coordination sites, forming chelate rings.
This type of complex can also display octahedral geometry. For this complex, possible stereoisomers are created due to different arrangements of the ligands, which are:
The complex \([\text{CrCl}_2(\text{ox})_2]^{3-}\) can have:
Thus, \([\text{CrCl}_2(\text{ox})_2]^{3-}\) has 3 stereoisomers.
Conclusively, the number of stereoisomers for \([\text{CrCl}_3(\text{py})_3]\) is 2, and for \([\text{CrCl}_2(\text{ox})_2]^{3-}\) is 3. Thus the correct answer is 2 & 3.
1. $\left[\mathrm{CrCl}_{3}(\mathrm{py})_{3}\right]$: - Facial and meridional isomers are possible. - Total stereoisomers = 2.
2. $\left[\mathrm{CrCl}_{2}(\mathrm{ox})_{2}\right]^{3-}$:
- Geometrical isomers: cis and trans.
- Optical isomers for cis: 2.
- Optical isomers for trans: 1.
- Total stereoisomers = 3.
Therefore, the correct answer is (3) 2 & 3.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
| List I (Substances) | List II (Element Present) |
| (A) Ziegler catalyst | (I) Rhodium |
| (B) Blood Pigment | (II) Cobalt |
| (C) Wilkinson catalyst | (III) Iron |
| (D) Vitamin B12 | (IV) Titanium |
| List-I (Complex ion) | List-II (Spin only magnetic moment in B.M.) |
|---|---|
| (A) [Cr(NH$_3$)$_6$]$^{3+}$ | (I) 4.90 |
| (B) [NiCl$_4$]$^{2-}$ | (II) 3.87 |
| (C) [CoF$_6$]$^{3-}$ | (III) 0.0 |
| (D) [Ni(CN)$_4$]$^{2-}$ | (IV) 2.83 |
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)