A molecule has a zero dipole moment if it is symmetric, and the bond dipoles cancel each other out. Let us analyze each compound:
\(\text{H}_2\): Diatomic, nonpolar, symmetric. - Dipole moment = 0.
\(\text{CO}_2\): Linear molecule, symmetric. - Dipole moment = 0.
\(\text{BF}_3\): Planar triangular structure, symmetric. - Dipole moment = 0.
\(\text{CH}_4\): Tetrahedral geometry, symmetric. - Dipole moment = 0.
\(\text{SiF}_4\): Tetrahedral geometry, symmetric. - Dipole moment = 0.
\(\text{BeF}_2\): Linear molecule, symmetric. - Dipole moment = 0.
Molecules with nonzero dipole moments:
\(\text{HF}\): Polar molecule, asymmetric.
\(\text{H}_2\text{S}\): Bent structure, asymmetric.
\(\text{NH}_3\): Trigonal pyramidal structure, asymmetric.
\(\text{CHCl}_3\): Tetrahedral, but asymmetric due to \(\text{Cl}\).
\(\text{H}_2\text{O}\): Bent structure, asymmetric.
Conclusion: The compounds with zero dipole moment are:
\[\text{H}_2, \, \text{CO}_2, \, \text{BF}_3, \, \text{CH}_4, \, \text{SiF}_4, \, \text{BeF}_2.\]
The number of such compounds is:
\[6.\]
Final Answer: 6.



The figure shows a pipe with cross-section area 10 \( cm^2 \). Water flows from one end with velocity 20 cm/s. The other end of the pipe is closed and consists of 10 holes each of area 30 \( mm^2 \). Find the velocity of water coming out from each hole: 
Which of the following best represents the temperature versus heat supplied graph for water, in the range of \(-20^\circ\text{C}\) to \(120^\circ\text{C}\)? 