A molecule has a zero dipole moment if it is symmetric, and the bond dipoles cancel each other out. Let us analyze each compound:
\(\text{H}_2\): Diatomic, nonpolar, symmetric. - Dipole moment = 0.
\(\text{CO}_2\): Linear molecule, symmetric. - Dipole moment = 0.
\(\text{BF}_3\): Planar triangular structure, symmetric. - Dipole moment = 0.
\(\text{CH}_4\): Tetrahedral geometry, symmetric. - Dipole moment = 0.
\(\text{SiF}_4\): Tetrahedral geometry, symmetric. - Dipole moment = 0.
\(\text{BeF}_2\): Linear molecule, symmetric. - Dipole moment = 0.
Molecules with nonzero dipole moments:
\(\text{HF}\): Polar molecule, asymmetric.
\(\text{H}_2\text{S}\): Bent structure, asymmetric.
\(\text{NH}_3\): Trigonal pyramidal structure, asymmetric.
\(\text{CHCl}_3\): Tetrahedral, but asymmetric due to \(\text{Cl}\).
\(\text{H}_2\text{O}\): Bent structure, asymmetric.
Conclusion: The compounds with zero dipole moment are:
\[\text{H}_2, \, \text{CO}_2, \, \text{BF}_3, \, \text{CH}_4, \, \text{SiF}_4, \, \text{BeF}_2.\]
The number of such compounds is:
\[6.\]
Final Answer: 6.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,