Step 1: Write the structure of ethylene
Ethylene (\(C_2H_4\)) has the structural formula:
\[
H_2C = CH_2
\]
Each carbon atom forms three sigma (σ) bonds — two with hydrogen atoms and one with the other carbon atom — and shares one pi (π) bond between the two carbon atoms.
Step 2: Count σ (sigma) bonds
• 4 C–H bonds → 4 σ bonds
• 1 C–C single bond → 1 σ bond
Total σ bonds = 4 + 1 = 5 σ bonds.
Step 3: Count π (pi) bonds
• The double bond between the two carbon atoms consists of one σ and one π bond.
Therefore, π bonds = 1.
Step 4: Final answer
5 and 1