To determine the number of ambidentate ligands among the given species, we first need to understand what constitutes an ambidentate ligand. An ambidentate ligand can coordinate to a metal ion through two different atoms. We will analyze each ligand:
Thus, the ambidentate ligands among the listed are \(\text{NO}_2^{-}\), \(\text{SCN}^{-}\), and \(\text{CN}^{-}\). This gives us a total of 3 ambidentate ligands, which is within the specified range (3,3).
Step 1: Define ambidentate ligands
Ambidentate ligands are ligands that can coordinate to a metal center through two different atoms.
Step 2: Analyze the ligands
Step 3: Count ambidentate ligands
Ambidentate ligands are:
\[ \text{NO}_2^-, \, \text{SCN}^-, \, \text{CN}^-. \] Total number = 3.
Thus, the correct answer: 3.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)