Question

\([Ni(CN)_4]^{2-}\)

Hint:

Strong field ligands (like CN$^-$) induce low-spin configurations, leading to square planar geometry.

Answer 1

- Oxidation State of Ni: \[ x + 4(-1) = -2 \Rightarrow x = +2 \] So, Ni is in the \( +2 \) oxidation state. 
- Electronic Configuration of \( Ni^{2+} \): \[ [Ar] 3d^8 4s^0 \] 
- Nature of Ligand: 
- Cyanide \( (CN^-) \) is a strong field ligand, which causes pairing of electrons.
- The square planar geometry is preferred.
- Unpaired Electrons & Hybridization: 
- Hybridization: \( dsp^2 \) 
- Unpaired electrons: 0 
- Geometry: Square Planar