NaOH is a strong base. What will be pH of \(5.0\times10^{-2}\) M NaOH solution ? (\(\log 2 = 0.3\))
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- 14.00
- 13.70
- 13.00
- 12.70
The Correct Option is D
Solution and Explanation
\(\mathrm{pOH} = -\log(5\times10^{-2}) = 2 - \log 5\).
\(\log 5 = \log\frac{10}{2} = 1 - 0.3 = 0.7\), so \(\mathrm{pOH} = 2 - 0.7 = 1.3\).
\(\mathrm{pH} = 14 - 1.3 = 12.7\).
Answer: (4) 12.70
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