The process used to obtain sodium hydroxide from brine is called the chlor-alkali process. It involves the electrolysis of brine (concentrated aqueous solution of sodium chloride) using a diaphragm cell or a mercury cell.
In the chlor-alkali process, brine is electrolyzed using inert electrodes (e.g., graphite for anode and steel for cathode). During the electrolysis:
At the cathode (reduction): Sodium ions (\(\text{Na}^+\)) are reduced to sodium metal (\(\text{Na}\)), which immediately reacts with water to form sodium hydroxide (\(\text{NaOH}\)) and hydrogen gas (\(\text{H}_2\)).
\[ 2\text{Na}^+(\text{aq}) + 2e^- \rightarrow 2\text{Na}(\text{s}) \] \[ 2\text{Na}(\text{s}) + 2\text{H}_2\text{O}(\text{l}) \rightarrow 2\text{NaOH}(\text{aq}) + \text{H}_2(\text{g}) \]
At the anode (oxidation): Chloride ions (\(\text{Cl}^-\)) are oxidized to chlorine gas (\(\text{Cl}_2\)).
\[ 2\text{Cl}^-(\text{aq}) \rightarrow \text{Cl}_2(\text{g}) + 2e^- \]
The overall reaction is:
\[ 2\text{NaCl}(\text{aq}) + 2\text{H}_2\text{O}(\text{l}) \rightarrow 2\text{NaOH}(\text{aq}) + \text{H}_2(\text{g}) + \text{Cl}_2(\text{g}) \]
Gases produced:
Uses of gases:
Chlorine (\(\text{Cl}_2\)):
Hydrogen (\(\text{H}_2\)):
| Case No. | Lens | Focal Length | Object Distance |
|---|---|---|---|
| 1 | \(A\) | 50 cm | 25 cm |
| 2 | B | 20 cm | 60 cm |
| 3 | C | 15 cm | 30 cm |
| Case No. | Lens | Focal Length | Object Distance |
|---|---|---|---|
| 1 | \(A\) | 50 cm | 25 cm |
| 2 | B | 20 cm | 60 cm |
| 3 | C | 15 cm | 30 cm |