Question:

\(N\)-point DFT using FFT algorithms (radix-2) requires the following complex multiplications

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DFT complexity: \[ O(N^2) \] FFT complexity: \[ O(N\log_2 N) \] This reduction is the main reason FFT is widely used in DSP applications.
Updated On: Jun 25, 2026
  • \(N\)
  • \(2N\)
  • \(\log_2 N\)
  • \(N\log_2 N\)
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The Correct Option is D

Solution and Explanation

Concept: The Fast Fourier Transform (FFT) is an efficient algorithm for computing the DFT. A direct DFT requires \[ N^2 \] complex multiplications. FFT drastically reduces this computational burden.

Step 1:
Recall FFT complexity.
For radix-2 FFT, \[ \text{Complex Multiplications} = \frac{N}{2}\log_2 N. \] The order of growth is \[ O(N\log_2 N). \]

Step 2:
Compare with the given options.
Among the available choices, the correct FFT complexity is represented by \[ N\log_2 N. \]

Step 3:
Final answer.
\[ \boxed{N\log_2 N} \]
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