$MgSO_4$ on reaction with $NH_4 OH $ and $ Na_2 HPO_4$ forms a white crystalline precipitate. What is its formula?
- $Mg (NH_4)PO_4$
- $Mg_3 (PO_4)_2$
- $MgCI_2.MgSO_4$
- $MgSO_4$
The Correct Option is A
Solution and Explanation
$\hspace73mm + Na_2 SO_4 + H_2 O$
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