Question:

Metallic sodium does not react normally with :

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Sodium displaces hydrogen from acidic X-H bonds (N-H of ammonia, terminal alkyne C-H, O-H of alcohols); an internal alkyne has no acidic hydrogen.
Updated On: Nov 4, 2026
  • gaseous ammonia
  • But-2-yne
  • Ethyne
  • tert-butyl alcohol
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The Correct Option is B

Solution and Explanation

Gaseous \(\mathrm{NH_3}\): \(2\mathrm{Na} + 2\mathrm{NH_3} \to 2\mathrm{NaNH_2} + \mathrm{H_2}\).
Ethyne (terminal alkyne, acidic sp C-H): \(\mathrm{HC\equiv CH} + \mathrm{Na} \to \mathrm{HC\equiv CNa} + \frac12\mathrm{H_2}\).
tert-Butyl alcohol: \(2(\mathrm{CH_3})_3\mathrm{COH} + 2\mathrm{Na} \to 2(\mathrm{CH_3})_3\mathrm{CONa} + \mathrm{H_2}\).
But-2-yne, \(\mathrm{CH_3C\equiv CCH_3}\), has no acidic hydrogen on the triple-bonded carbons, so sodium does not react normally with it.
Answer: (2) But-2-yne
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