Question

Maximum shear stress in a Mohr's Circle is

• A. Equal to the radius of Mohr's circle
• B. Greater than the radius of Mohr's circle
• C. Less than the radius of Mohr's circle
• D. Independent of the radius of Mohr's circle

Hint:

Remember, \[ \boxed{ \tau_{\max} = \frac{\sigma_1-\sigma_2}{2} = \text{Radius of Mohr's circle}. } \]

Answer 1

The Correct Option is A

Step 1: Recall the radius of Mohr's circle. The radius of Mohr's circle is \[ R=\frac{\sigma_1-\sigma_2}{2}, \] where \(\sigma_1\) and \(\sigma_2\) are the principal stresses.

Step 2: Determine the maximum shear stress. The maximum shear stress is equal to the radius of the circle. Thus, \[ \tau_{\max} = R = \frac{\sigma_1-\sigma_2}{2}. \] Hence, \[ \boxed{\text{Maximum shear stress = Radius of Mohr's circle}.} \] Therefore, \[ \boxed{(A)} \] is the correct answer.