Question

\(\mathrm{SO_2}\) reacts with chlorine in the presence of charcoal and gives a compound \(X\). \(X\) on reaction with phosphorus gives \(\mathrm{SO_2}\) and \(Y\). The shape of \(Y\) is

• A. Pyramidal
• B. Tetrahedral
• C. Trigonal bipyramidal
• D. Angular

Hint:

Remember: \[ \boxed{ \mathrm{SO_2+Cl_2 \rightarrow SO_2Cl_2} } \] and \[ \boxed{ \mathrm{PCl_5} } \] has a trigonal bipyramidal structure.

Answer 1

The Correct Option is C

Step 1: Identify compound \(X\). Sulphur dioxide reacts with chlorine in the presence of charcoal to form sulphuryl chloride. \[ \boxed{ \mathrm{SO_2+Cl_2 \xrightarrow{\text{charcoal}} SO_2Cl_2} } \] Hence, \[ X=\mathrm{SO_2Cl_2}. \]

Step 2: Reaction of \(X\) with phosphorus. Sulphuryl chloride reacts with phosphorus to produce phosphorus pentachloride and sulphur dioxide. \[ \boxed{ \mathrm{P+SO_2Cl_2 \rightarrow PCl_5+SO_2} } \] Thus, \[ Y=\mathrm{PCl_5}. \]

Step 3: Determine the shape of \(Y\). According to VSEPR theory, \[ \mathrm{PCl_5} \] has \[ \boxed{\text{Trigonal bipyramidal geometry}.} \] Hence, the correct option is \[ \boxed{(C).} \]