Question:

\(\mathrm{FeX_2}\) and \(\mathrm{FeY_3}\) are known when x and y are :

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Fe3+ oxidises iodide to iodine, so FeI3 does not exist.
Updated On: Nov 4, 2026
  • x = F, Cl, Br, I and y = F, Cl, Br, I
  • x = F, Cl, Br and y = F, Cl, Br, I
  • x = F, Cl, Br, I and y = F, Cl, Br
  • x = Cl, Br, I and y = F, Cl, Br, I
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The Correct Option is C

Solution and Explanation

In \(\mathrm{FeX_2}\) iron is +2, which is a mild state; all halides FeF2, FeCl2, FeBr2, FeI2 are known, so x = F, Cl, Br, I.
In \(\mathrm{FeY_3}\) iron is +3. \(\mathrm{Fe^{3+}}\) is a good oxidant and \(\mathrm{I^-}\) a good reductant: \(2\mathrm{Fe^{3+}} + 2\mathrm{I^-} \to 2\mathrm{Fe^{2+}} + \mathrm{I_2}\). Hence FeI3 is not stable.
So y = F, Cl, Br only.
Answer: (3) x = F, Cl, Br, I and y = F, Cl, Br
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